20 Exam-Style Problems ยท Instant Feedback ยท Full Explanations
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Unit 1
Quadratic Functions & Equations
Standard Form\(f(x)=ax^2+bx+c\) โ vertex at \(x=-\frac{b}{2a}\)
โ 3rd term (\(k=2\)): \(\binom{5}{2}(2x)^3(3)^2=10\cdot8x^3\cdot9=720x^3\).
Rex says: Great job reviewing! ๐ฆ Now switch to the Problems tab and show me what you've got! Remember โ read each question carefully before choosing. You've totally got this! ๐ช
Q1 Quadratic ยท Medium
The vertex of \(f(x)=3x^2-12x+7\) is at the point:
๐ Solution
Vertex x-coordinate: \(x=-\dfrac{b}{2a}=-\dfrac{-12}{2(3)}=\dfrac{12}{6}=2\).
Substitute: \(f(2)=3(4)-12(2)+7=12-24+7=-5\).
โด Vertex is \((2,\ -5)\).
Q2 Quadratic ยท Hard
The equation \(x^2-4x+k=0\) has two complex (non-real) roots. Which of the following must be true?
๐ Solution
For complex (non-real) roots the discriminant must be negative.
\(\Delta=b^2-4ac=(-4)^2-4(1)(k)=16-4k\).
We need \(16-4k<0\) โ \(4k>16\) โ \(k>4\).
Q3 Complex Numbers ยท Medium
What is \((3+4i)(3-4i)\)?
๐ Solution
\((3+4i)(3-4i)=3^2-(4i)^2=9-16i^2=9-16(-1)=9+16=25\).
Note: (C) is a partially simplified expression, not a simplified answer. The correct simplified value is \(25\).
Q4 Complex Numbers ยท Hard
Simplify \(i^{47}\).
๐ Solution
Powers of \(i\) cycle with period 4: \(i^1=i,\ i^2=-1,\ i^3=-i,\ i^4=1\).
\(47\div4=11\) remainder \(3\).
Therefore \(i^{47}=i^3=-i\).
Q5 Polynomials ยท Medium
When \(f(x)=2x^3-5x^2+3x-7\) is divided by \((x-2)\), the remainder is:
๐ Solution
By the Remainder Theorem, the remainder = \(f(2)\).
\(f(2)=2(8)-5(4)+3(2)-7=16-20+6-7=-5\).
Q6 Polynomials ยท Hard
How many positive real zeros does \(f(x)=x^4-3x^3+x^2+3x-2\) have, according to Descartes' Rule of Signs?
๐ Solution
Count sign changes in the coefficients: \(+1,\,-3,\,+1,\,+3,\,-2\).
Sign changes: \(+โ-\) (1), \(-โ+\) (2), \(+โ+\) (no), \(+โ-\) (3).
There are 3 sign changes, so there are 3 or 1 positive real zeros.
Q7 Rational Functions ยท Medium
Which of the following is the horizontal asymptote of \(f(x)=\dfrac{4x^2-1}{2x^2+3x}\)?
๐ Solution
Degrees of numerator and denominator are both 2 (equal).
Horizontal asymptote = ratio of leading coefficients: \(\dfrac{4}{2}=2\).
โด \(y=2\).
Q8 Radical & Exponential ยท Medium
Solve for \(x\): \(4^{x+1}=8^{x-1}\).
๐ Solution
Write both sides as powers of 2: \(4=2^2\) and \(8=2^3\).
\(2^{2(x+1)}=2^{3(x-1)}\) โ \(2x+2=3x-3\) โ \(x=5\).
Q9 Logarithms ยท Medium
Evaluate: \(\log_4 128\).
๐ Solution
Express in base 2: \(4=2^2,\;128=2^7\).
\(\log_4 128=\dfrac{\log_2 128}{\log_2 4}=\dfrac{7}{2}\).
Q10 Logarithms ยท Hard
Solve: \(\log_2(x)+\log_2(x-6)=4\).
๐ Solution
\(\log_2[x(x-6)]=4\) โ \(x(x-6)=16\) โ \(x^2-6x-16=0\).
Factor: \((x-8)(x+2)=0\) โ \(x=8\) or \(x=-2\).
Domain: \(x>0\) and \(x>6\), so \(x>6\). Reject \(x=-2\).
โด \(x=8\).
Q11 Sequences ยท Medium
The sum of the first 10 terms of an arithmetic sequence with \(a_1=3\) and common difference \(d=4\) is:
What is the sum of the infinite geometric series \(8-4+2-1+\cdots\)?
๐ Solution
\(a_1=8,\;r=-\dfrac{1}{2}\). Since \(|r|=\dfrac{1}{2}<1\), the series converges.
\(S=\dfrac{a_1}{1-r}=\dfrac{8}{1-(-\frac{1}{2})}=\dfrac{8}{\frac{3}{2}}=\dfrac{16}{3}\).
Q13 Matrices ยท Medium
If \(A=\begin{pmatrix}2&-1\\4&3\end{pmatrix}\), what is \(\det(A)\)?
๐ Solution
\(\det(A)=ad-bc=(2)(3)-(-1)(4)=6+4=10\).
Q14 Matrices ยท Hard
Using Cramer's Rule, solve for \(y\) in the system: \(2x+y=5\) and \(x-3y=-1\).
The equation \(\dfrac{(x-2)^2}{16}+\dfrac{(y+1)^2}{9}=1\) represents an ellipse. What is the length of its major axis?
๐ Solution
From the standard form \(\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1\):
Here \(a^2=16\), so \(a=4\). The major axis has length \(2a=2(4)=8\).
Q16 Conics ยท Hard
The hyperbola \(\dfrac{x^2}{9}-\dfrac{y^2}{16}=1\) has asymptotes:
๐ Solution
For hyperbola \(\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1\), asymptotes are \(y=\pm\dfrac{b}{a}x\).
Here \(a^2=9\Rightarrow a=3\) and \(b^2=16\Rightarrow b=4\).
โด Asymptotes: \(y=\pm\dfrac{4}{3}x\).
Q17 Probability ยท Medium
How many different 4-letter arrangements (order matters) can be made from the letters in "MATH"?
๐ Solution
All 4 letters in "MATH" are distinct, and we arrange all 4.
\(P(4,4)=4!=4\times3\times2\times1=24\).
Q18 Binomial Theorem ยท Hard
What is the coefficient of \(x^3\) in the expansion of \((x-2)^5\)?
๐ Solution
General term: \(\binom{5}{k}(x)^{5-k}(-2)^k\). For \(x^3\), we need \(5-k=3\), so \(k=2\).
Term: \(\binom{5}{2}(x)^3(-2)^2=10\cdot x^3\cdot4=40x^3\).
โด Coefficient of \(x^3\) is \(40\).
Q19 Exponential Functions ยท Hard
A population doubles every 5 years. Starting with 1,000 people, how many will there be after 20 years?
๐ Solution
The number of doubling periods in 20 years: \(\dfrac{20}{5}=4\).
Population \(=1000\times2^4=1000\times16=16{,}000\).
Q20 Rational Functions ยท Hard
Which value of \(x\) is NOT in the domain of \(f(x)=\dfrac{x+3}{x^2-x-6}\)?
๐ Solution
Factor the denominator: \(x^2-x-6=(x-3)(x+2)\).
The denominator equals zero when \(x=3\) or \(x=-2\).
Note: \(x=-3\) is NOT excluded (the numerator \(x+3\) becomes 0 there, creating a hole, but the denominator โ 0 at \(x=-3\)).
Wait โ let's recheck: at \(x=-3\): \((-3)^2-(-3)-6=9+3-6=6\neq0\). So \(x=-3\) IS in the domain.
โด Values NOT in the domain: \(x=3\) and \(x=-2\).
๐ Answer Key & Explanations
Q1 โ Quadratic Vertex
โ Correct Answer: A) (2, โ5)
Vertex x-coord: \(x=-\frac{-12}{6}=2\). Then \(f(2)=12-24+7=-5\). Vertex: \((2,-5)\).
Q2 โ Discriminant
โ Correct Answer: C) k > 4
\(\Delta=16-4k<0 \Rightarrow k>4\) for two complex roots.
Q3 โ Complex Conjugate Product
โ Correct Answer: A) 25
\((3+4i)(3-4i)=9-16i^2=9+16=25\).
Q4 โ Powers of i
โ Correct Answer: D) โi
\(47=4(11)+3\), so \(i^{47}=i^3=-i\).
Q5 โ Remainder Theorem
โ Correct Answer: B) โ5
\(f(2)=16-20+6-7=-5\).
Q6 โ Descartes' Rule
โ Correct Answer: B) 3 or 1
Coefficients \(+,-,+,+,-\) give 3 sign changes โ 3 or 1 positive real zeros.
Q7 โ Horizontal Asymptote
โ Correct Answer: B) y = 2
Equal degrees โ HA = leading coefficient ratio = \(4/2=2\).