20 carefully verified problems across all AMC 8 topics — with concept review, examples, and detailed explanations.
Master these concepts before attempting the problems below.
The GCD is the largest divisor common to two numbers. The LCM is the smallest common multiple.
To find GCD: use prime factorization — take the lowest powers. For LCM: take the highest powers.
GCD(12, 18)? Factors: 12 = 2²×3, 18 = 2×3². GCD = 2¹×3¹ = 6. LCM = 2²×3² = 36.
✓ GCD = 6, LCM = 36To add/subtract fractions: find common denominator. To multiply: multiply tops and bottoms. To divide: multiply by the reciprocal.
(3/4) ÷ (1/2) = (3/4) × (2/1) = 6/4 = 3/2
✓ Answer: 3/2Percent change measures the relative increase or decrease from an original value.
Successive percent changes: a 20% increase then 20% decrease does NOT return to the original! Multiply factors: 1.2 × 0.8 = 0.96 (4% net decrease).
Price $80 rises to $100. % Change = (100−80)/80 × 100 = 20/80 × 100 = 25%
✓ 25% increaseSolve by isolating the variable. When multiplying/dividing by a negative, flip the inequality sign.
Word problems: translate "is" → =, "more than" → +, "less than" → −, "times" → ×.
3x + 5 = 20. Subtract 5: 3x = 15. Divide by 3: x = 5.
✓ x = 5Critical formulas for common shapes:
Triangle with base 8 and height 5: A = ½ × 8 × 5 = 20
✓ Area = 20Probability = (favorable outcomes) ÷ (total outcomes). For independent events, multiply probabilities.
Bag has 3 red, 2 blue balls. P(red) = 3/5. Draw 2 with replacement: P(both red) = (3/5)×(3/5) = 9/25.
✓ P = 9/25Mean = sum ÷ count. Median = middle value when sorted. Mode = most frequent. Range = max − min.
Data: {3, 7, 7, 9, 14}. Mean = 40/5 = 8. Median = 7. Mode = 7. Range = 14−3 = 11.
✓ Mean=8, Median=7, Mode=7, Range=11Fundamental Counting Principle: multiply choices at each step. Combinations (order doesn't matter): C(n,k) = n! / (k!(n−k)!)
How many ways to choose 2 from 5? C(5,2) = 5!/(2!×3!) = (5×4)/(2×1) = 10.
✓ 10 waysA ratio a:b means for every a of one thing, there are b of another. Cross-multiply to solve proportions.
Ratio of boys:girls = 3:4 in a class of 35. Boys = 3/(3+4) × 35 = 3/7 × 35 = 15.
✓ 15 boysArithmetic: constant difference d. nth term = a + (n−1)d. Sum of n terms = n/2 × (first + last).
1+2+3+...+10 = 10×11/2 = 55. Sum of first 5 odd numbers = 5² = 25.
✓ 55 and 25AMC 8 style — 5 choices per question. Select your answer and check immediately, or submit all at the end.
Or check individual questions using the Check buttons above.
Detailed step-by-step solutions for all 20 problems