Rex 🦕
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📚 Concepts
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📚 Geometry — All Units
📐
Unit 1: Lines, Angles & Proofs
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SUPPLEMENTARY
Angles sum to 180°
COMPLEMENTARY
Angles sum to 90°
VERTICAL ANGLES
Equal (across vertex)
LINEAR PAIR
Adjacent; sum = 180°
📌 KEY THEOREMS
Parallel lines cut by transversal:
• Alternate interior ∠s → Equal
• Corresponding ∠s → Equal
• Co-interior (same-side) → 180°
Exterior angle = sum of 2 non-adj. interior ∠s
• Alternate interior ∠s → Equal
• Corresponding ∠s → Equal
• Co-interior (same-side) → 180°
Exterior angle = sum of 2 non-adj. interior ∠s
⭐ MEMORIZE
- Vertical angles are ALWAYS equal
- Linear pair ALWAYS sums to 180°
- Alternate angles need PARALLEL lines
- Exterior angle theorem: ∠ext = ∠A + ∠B
💡 EXAMPLE
Two parallel lines are cut by a transversal. One co-interior angle is 65°. Find the other.
Co-interior angles are supplementary.
Other angle = 180° − 65° = 115°
Other angle = 180° − 65° = 115°
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Unit 2: Triangles & Congruence/Similarity
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ANGLE SUM
∠A + ∠B + ∠C = 180°
PYTHAGOREAN
a² + b² = c²
CONGRUENCE
SSS, SAS, ASA, AAS, HL
SIMILARITY
AA, SAS~, SSS~
📌 AREA & SPECIAL TRIANGLES
Area = ½ × base × height
30-60-90: sides → 1 : √3 : 2
45-45-90: sides → 1 : 1 : √2
Midsegment = ½ × parallel side
Similar ratio k → Area ratio k²
30-60-90: sides → 1 : √3 : 2
45-45-90: sides → 1 : 1 : √2
Midsegment = ½ × parallel side
Similar ratio k → Area ratio k²
⭐ MEMORIZE
- SSA is NOT a congruence postulate (ambiguous case)
- CPCTC: Corresponding Parts of Congruent Triangles are Congruent
- Isosceles: base angles are equal
- Centroid divides median in 2:1 ratio
💡 EXAMPLE
Two similar triangles have sides in ratio 3:5. What is the ratio of their areas?
Area ratio = (3)² : (5)² = 9 : 25
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Unit 3: Quadrilaterals & Polygons
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PARALLELOGRAM
Opp sides ∥ & equal
RECTANGLE
Parallelogram + 90° angles
RHOMBUS
All sides equal; ⊥ diags
SQUARE
Rectangle + Rhombus
📌 POLYGON FORMULAS
Interior angle sum = (n − 2) × 180°
Each interior angle (regular) = (n−2)×180° / n
Exterior angle sum = ALWAYS 360°
Each exterior angle (regular) = 360° / n
Parallelogram area = base × height
Trapezoid area = ½(b₁ + b₂) × h
Each interior angle (regular) = (n−2)×180° / n
Exterior angle sum = ALWAYS 360°
Each exterior angle (regular) = 360° / n
Parallelogram area = base × height
Trapezoid area = ½(b₁ + b₂) × h
⭐ MEMORIZE
- Parallelogram: diagonals BISECT each other
- Rectangle: diagonals are EQUAL length
- Rhombus: diagonals are PERPENDICULAR
- Square: diagonals bisect, equal, perpendicular
- Trapezoid: exactly one pair of parallel sides
💡 EXAMPLE
Find the sum of interior angles of a hexagon.
(n − 2) × 180° = (6 − 2) × 180° = 4 × 180° = 720°
⭕
Unit 4: Circles
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CIRCUMFERENCE
C = 2πr = πd
AREA
A = πr²
ARC LENGTH
(θ/360)·2πr
SECTOR AREA
(θ/360)·πr²
📌 CIRCLE ANGLE THEOREMS
Central angle = Intercepted arc
Inscribed angle = ½ × Intercepted arc
Tangent-chord angle = ½ arc
Two chords (inside) = ½(arc₁ + arc₂)
Two secants (outside) = ½|arc₁ − arc₂|
Tangent² = external × whole secant
Chord-chord: AE × EB = CE × ED
Inscribed angle = ½ × Intercepted arc
Tangent-chord angle = ½ arc
Two chords (inside) = ½(arc₁ + arc₂)
Two secants (outside) = ½|arc₁ − arc₂|
Tangent² = external × whole secant
Chord-chord: AE × EB = CE × ED
⭐ MEMORIZE
- Inscribed angle in semicircle = 90°
- Tangent ⊥ radius at point of tangency
- Equal chords are equidistant from center
- Inscribed angles subtending same arc are equal
💡 EXAMPLE
A central angle is 80°. What is the inscribed angle that intercepts the same arc?
Inscribed angle = ½ × central angle = ½ × 80° = 40°
📦
Unit 5: 3D Figures & Coordinate Geometry
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📌 VOLUME & SURFACE AREA
Prism: V = Bh, SA = 2B + Ph
Cylinder: V = πr²h, SA = 2πr²+2πrh
Pyramid: V = ⅓Bh
Cone: V = ⅓πr²h, SA = πr²+πrl
Sphere: V = ⁴⁄₃πr³, SA = 4πr²
Distance = √[(x₂−x₁)²+(y₂−y₁)²]
Midpoint = ((x₁+x₂)/2,(y₁+y₂)/2)
Slope = (y₂−y₁)/(x₂−x₁)
Perpendicular slopes: m₁ × m₂ = −1
Cylinder: V = πr²h, SA = 2πr²+2πrh
Pyramid: V = ⅓Bh
Cone: V = ⅓πr²h, SA = πr²+πrl
Sphere: V = ⁴⁄₃πr³, SA = 4πr²
Distance = √[(x₂−x₁)²+(y₂−y₁)²]
Midpoint = ((x₁+x₂)/2,(y₁+y₂)/2)
Slope = (y₂−y₁)/(x₂−x₁)
Perpendicular slopes: m₁ × m₂ = −1
⭐ MEMORIZE
- Cone & Pyramid volume = ⅓ × (prism/cylinder volume)
- Sphere SA = 4πr² (4 great circles)
- l in cone formula = slant height = √(r² + h²)
- Scale factor k → Volume scales by k³
💡 EXAMPLE
A cone has radius 3 cm and height 4 cm. Find its volume.
V = ⅓πr²h = ⅓ × π × 9 × 4 = 12π ≈ 37.7 cm³