\(\sin^2 x = \tfrac{1-\cos 2x}{2}\quad \cos^2 x = \tfrac{1+\cos 2x}{2}\)
\(\int \sin^m x\cos^n x\,dx\): if \(m\) odd, factor out \(\sin x\) and substitute \(u=\cos x\). If \(n\) odd, substitute \(u=\sin x\).
If both powers even, use the half-angle identities above.
Example
\(\int \sin^2 x\,dx = \int\tfrac{1-\cos 2x}{2}\,dx = \tfrac{x}{2} - \tfrac{\sin 2x}{4} + C\)