MATHEMATICS · CALCULUS II

Essential Problems

A curated collection of 20 exam-style problems covering every major topic

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📚 Concept Review & Key Formulas
Topic 01 · Integration Techniques

Integration by Parts & Substitution

\(\int u\,dv = uv - \int v\,du\)
\(\int f(g(x))g'(x)\,dx = \int f(u)\,du,\quad u=g(x)\)

LIATE rule for IBP: choose \(u\) as Logarithm, Inverse trig, Algebraic, Trig, Exponential (in that priority order).

Topic 02 · Partial Fractions & Trig Sub

Rational Functions & Trig Substitution

For \(\sqrt{a^2-x^2}\): let \(x=a\sin\theta\)
For \(\sqrt{a^2+x^2}\): let \(x=a\tan\theta\)
For \(\sqrt{x^2-a^2}\): let \(x=a\sec\theta\)

Partial fractions decompose rational functions into simpler pieces before integrating.

Topic 03 · Improper Integrals

Convergence & Divergence

\(\int_1^{\infty}\frac{1}{x^p}\,dx\) converges iff \(p>1\)

Replace infinite limit with \(t\), integrate, then take \(\lim_{t\to\infty}\). Use comparison test when direct integration is difficult.

Topic 04 · Sequences & Series

Convergence Tests

Ratio Test: \(L=\lim_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right|\)
\(L<1\): converge · \(L>1\): diverge · \(L=1\): inconclusive
Alternating Series: converges if \(b_n\) decreasing \(\to 0\)
Topic 05 · Power Series

Taylor & Maclaurin Series

\(e^x = \sum_{n=0}^{\infty}\frac{x^n}{n!}\)   \(\sin x = \sum_{n=0}^{\infty}\frac{(-1)^n x^{2n+1}}{(2n+1)!}\)
\(\cos x = \sum_{n=0}^{\infty}\frac{(-1)^n x^{2n}}{(2n)!}\)   \(\frac{1}{1-x} = \sum_{n=0}^{\infty}x^n,\;|x|<1\)
Topic 06 · Polar Coordinates & Arc Length

Area & Length in Polar Form

Area: \(A=\frac{1}{2}\int_\alpha^\beta r^2\,d\theta\)
Arc Length: \(L=\int\sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2}\,dt\)
🔑 Must Memorize
p-series: p>1 converges geometric: |r|<1 converges → a/(1-r) LIATE for IBP Alternating: b_n↓→0 converges Radius R = 1/L (ratio test) sin²+cos²=1 identities Taylor center a: f(a)+f'(a)(x-a)+… Polar area = ½∫r²dθ
📝 Worked Example

Evaluate \(\int x e^x dx\).

Let \(u=x,\;dv=e^x dx\) (LIATE: Algebraic before Exponential)

Then \(du=dx,\;v=e^x\)

Answer: \(xe^x - e^x + C = e^x(x-1)+C\)

📝 20 Exam-Style Problems

Select the best answer. Explanations appear immediately after each choice.

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